1. c = 9cm

2. Thaleskreis über c

3. Parallele zu c im Abstand 4cm

4. Parallele ∩ Thaleskreis → Ecke C (mehrere Lösungen)

Der Inkreismittelpunkt ist der Schnittpunkt der Winkelhalbierenden!

A = (8.96, -0.66)
B = Point(Circle[A, 9])
f = Segment(A, B)
C_1 = Midpoint(f)
c = Semicircle(A, B)
D = Point(f)
g = OrthogonalLine(D, f)
d = Circle(D, 4)
E, F = Intersect(d, g)
j = Ray(D, F)
α = Angle(C_1, D, F)
G = Point(d)
H = Point(d)
e = CircleArc(D, G, H)
h = Segment(D, F)
i = Line(F, f)
I, C = Intersect(c, i)
d1, b, a, c_1 = Polygon(A, C, B)
β = Angle(A, C, B)
k, l = AngularBisector(b, f)
J = Point(k)
w_α = Ray(A, J)
m, n = AngularBisector(b, a)
K = Point(n)
w_γ = Ray(C, K)
Z = Intersect(w_α, w_γ)
p, q = AngularBisector(f, a)
L = Point(p)
r = Ray(B, L)
B' = Dilate(B, -0.5, Z)
C' = Dilate(C, -0.5, Z)
A' = Dilate(A, -0.5, Z)
d2, c', b', a' = Polygon(B', A', C')